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    tylerdee7
    Jul 11, 2020

    7/11 Homework: Boolean Algebra

    in CS Fundamentals for ACSL

    Simplify the following boolean algebra expression:



    10 comments
    0
    frong
    Jul 12, 2020

    ~~A +(~~B x ~~C) + ~~A x ~~~B

    = A + (B x C) x A x ~b

    =(A x A + B x C x A) x ~B

    = (A + A x B x C) x ~B

    = A x ~B + A x C x B x ~B

    Answer = A x ~B

    0
    kc5608
    Jul 14, 2020

    ~~A +(~~B x ~~C) + ~~A x ~~~B = A + (B x C) x A x ~b =(A x A + B x C x A) x ~B = (A + A x B x C) x ~B = A x ~B + A x C x B x ~B Answer = A x ~B

    0
    yuyifei08
    Jul 14, 2020

    ~(~(A + BC) + ~(A~B) )

    = ~~(A + BC) ~~(A~B)

    = (A + BC)A~B

    = AA~B + BCA~B

    = A~B + B~BCA

    = A~B + 0

    = A~B

    0
    ray.royw
    Jul 14, 2020

    ~~A+(~~B x ~~C) +~~A x ~~~B

    =A+(B xC) + A x ~B

    =(A+BC)A~B

    =AA~B+BCA~B

    =A~b+0

    =A~b


    0
    jessica301060
    Jul 15, 2020

    ~~A+(~~B * ~~C) +~~A * ~~~B = A+(B*C)+A*~B

    = A+B*C+A*~B

    = A+B*C+0

    = A+B*C

    0
    voyinger
    Jul 15, 2020

    ~ ( ~(A + B*C) + ~(A * ~B))


    = ~(~A * (~B + ~C) + ~A + B )

    = ~( ~A * ~B + ~A * ~C + ~A + B)

    = ~(~A*~B) * (A + C) * A * ~B

    = (A + B) * (A +C) * A * ~B

    =(A + A*C + B*A) * A * ~B

    = (A + A*C + A* B) * ~B

    =A*B~ + A*C*B

    0
    voyinger
    Jul 16, 2020

    correction:

    = ~ ~ (A + B*C) * ~ ~(A*~B)

    = (A + B*C) * A * ~B

    = (A + A * B * C) * ~B

    = A * ~B

    0
    Andy Ding
    Jul 15, 2020

    ~( ~ (A + BC) + ~ (A * ~ B)) = ~~(A + BC) * ~~ (A * ~ B) = (A + BC)(A * ~ B) = A + B*~BC = A

    0
    Andy Ding
    Jul 17, 2020

    ~( ~ (A + BC) + ~ (A * ~B)) = (~~(A + BC)(~~(A * ~ B)) = (A + BC)(A * ~B) = A(1 + BC)(~B) = A(~B)

    0
    lichencui
    Jul 16, 2020

    ~~A+(~~B x ~~C)+~~A x ~~~B

    =A+(B x C)A~B

    =(A+BC)A~B

    =AA~B+BCA~B

    =A~B+~BBCA

    =A~B+0

    =A~B

    0
    10 comments

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