2014-15 1. 3 2. 3 x 2^* 4 y*+ 2 x*- 2 y 2^*+ 4 x*+ 5 y*/ 2015-16 1. 23 2. -/*a ^-b c 2 b /c ^a 2

2010-11 3.00011 4.11110 2012-13 3.11101 4.11000

R2a 0 10 1 9 2 8 3 7 4 6 R2b 10 12 14 16 18 20 22 24 26 28 30... R1a * ** *** **** R1b ===== * ==== ** === *** == **** = R1c ***** ***** ***** *****... R22a 10 R22b 1.78333333... R22c 2 R22d 0

r3.a 1, 3, 6, 10, 15, 21, 28, 36, 45, 55 r3.b 0, 2, 1, 4, 3, 5, 4, 6, 5, 7 r3.c 5, 20, 60, 120, 120 r3.d 1, 2, 8, 64 r7.a 1 2 3 4 5 6 7 8 9 r7.b 1 3 5 7 9 r7.c 10 9 8 7 6 5 4 3 2 r7.d 0 1 2 3 4 5 6 7 8 9 r7.e 1 2 4 8 r7.f 2 4 6 8 r21.a 2 4 7 11 16 r21.b 4 9 16 r21.c 10 7

you can't put R4 into codiva because there are undefined variables

R2 = 0 R3 = because you've already defined mystery as a int so you don't have to define it again R1 = a and c are constants, they are also integers, b and d are floating-point numbers R4 = m * ( √ (1 + v / c) / √ (1 - v / c) - 1) = dm, π * r * r * h = volume, 4 * π * r^3 / 3 = volume, √ (x^2 + y^2) = z

the value of v won't change because you are basically dividing x by itself and then multiplying that by 10.